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🧪 Gas Laws

Charles's Law Calculator

Solve any of initial or final volume and temperature for a fixed gas at constant pressure, using V₁/T₁ = V₂/T₂. Volume is directly proportional to absolute temperature — heat the gas, it expands.

V₁/T₁ = V₂/T₂
Constant pressure
Temperature in kelvin
Solve any value
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Charles's Law — Quick answer

At constant pressure, a gas's volume is directly proportional to its absolute temperature (in kelvin).

V₁ / T₁ = V₂ / T₂ (T in kelvin)
V₂ = V₁·T₂ / T₁ · T₂ = T₁·V₂ / V₁

Worked example: 2 L at 300 K heated to 600 K. V₂ = 2 × 600 / 300 = 4 L.

2 L of gas at 300 K, heated

TemperatureVolumeNote
300 K (27 °C)2 Lstart
450 K3 L×1.5
600 K4 Ldouble temp

Used for: hot-air balloons, engines, thermometers, gas heating.

🧪 Charles's Law Calculator

Leave the one unknown blank. Temperatures must be in kelvin (°C + 273.15); both volumes share a unit.

Initial volume V₁
Initial temp T₁
Final volume V₂
Final temp T₂

⚠️ Temperatures must be absolute — in kelvin. Convert from Celsius with T(K) = °C + 273.15 (so 27 °C = 300 K). Using Celsius directly gives wrong answers. Pressure and the amount of gas are assumed constant.

Charles's Law describes how a fixed amount of gas behaves when you change its temperature at constant pressure: the volume is directly proportional to the absolute temperature, so V₁/T₁ = V₂/T₂. Heat the gas and it expands; cool it and it contracts — in exact proportion to the temperature measured in kelvin. The one rule that trips people up is that temperature must be absolute: a gas at 600 K really does occupy twice the volume it has at 300 K, but 600 °C and 300 °C are not in a 2:1 ratio at all.

Reviewed: June 19, 2026 · Author: Naveen P N, Founder — AI Calculator · Verified against: Charles's Law as the isobaric case of PV = nRT.

The Charles's Law equations

Charles's Law
V₁ / T₁ = V₂ / T₂ (T in kelvin)
Final volume
V₂ = V₁ × T₂ / T₁
Kelvin conversion
T(K) = T(°C) + 273.15

The ratio of volume to absolute temperature is a constant for the gas while pressure and amount stay fixed. To find any one quantity, set the two ratios equal and cross-multiply. Volume units cancel, so litres or millilitres both work, but the temperatures must be in kelvin — the proportionality is to absolute temperature, measured from absolute zero, not from the freezing point of water.

Worked example — heating a gas

Scenario: A 2-litre sample of gas at 300 K (27 °C) is heated to 600 K at constant pressure. What is the new volume?

Final volume
V₂ = 2 L × 600 K / 300 K = 4 L
Check the ratio
2 / 300 = 0.00667 = 4 / 600 ✓

Doubling the absolute temperature doubles the volume to 4 litres — the ratio V/T stays at 0.00667 L/K throughout. Heat the same gas to only 450 K and it would expand to 3 litres (a factor of 1.5, matching 450/300). Note that if you had wrongly used Celsius — 27 °C to 327 °C — you would get a completely different and incorrect answer, which is why the kelvin scale is essential here.

Frequently Asked Questions

What is Charles's Law?

At constant pressure, gas volume is directly proportional to absolute temperature: V₁/T₁ = V₂/T₂. Double the kelvin, double the volume.

How do I find the new volume?

V₂ = V₁·T₂/T₁. e.g. 2 L × 600 K ÷ 300 K = 4 L. New temp is T₂ = T₁·V₂/V₁.

Why must temperature be in kelvin?

The law uses absolute temperature from absolute zero. Add 273.15 to °C. Celsius gives wrong, even negative, volumes.

What happens when you heat a gas?

It expands in proportion to kelvin. 300 K → 330 K (+10%) grows volume by 10%. Basis of hot-air balloons.

Does pressure stay constant?

Yes — it's the isobaric case. If P changes too, use P₁V₁/T₁ = P₂V₂/T₂ or PV = nRT.

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