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🧪 Reaction Yields

Percent Yield Calculator

Enter the actual and theoretical yield to get the percent yield — or enter the percent and one yield to solve the other. Works in grams or moles for any reaction.

Percent yield
Solve actual / theoretical
Grams or moles
Yield check
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Percent yield — Quick answer

Percent yield is what you actually got as a fraction of the most you could have got, times 100.

percent yield = (actual / theoretical) × 100
actual = theoretical × %/100 · theoretical = actual ÷ (%/100)

Worked example: actual = 8.5 g, theoretical = 10 g. Percent yield = (8.5/10)×100 = 85%.

Actual yield from a 10 g theoretical

Percent yieldActual yieldRating
90%9.0 gexcellent
75%7.5 ggood
50%5.0 gpoor

Used for: lab reports, synthesis efficiency, process optimisation.

🧪 Percent Yield Calculator

Enter any two of actual yield, theoretical yield and percent yield (yields in the same unit).

Percent yield
Actual yield
Theoretical yield
Lost to inefficiency

⚠️ Actual and theoretical yield must share the same unit. A result above 100% means the product is wet or impure, or the theoretical value is wrong — dry, purify and recheck.

Every reaction has a best-case ceiling — the theoretical yield you would get if the chemistry went perfectly and you lost nothing. Reality always falls short: side reactions, incomplete conversion and losses in handling mean the actual yield is smaller. The percent yield measures how close you came, as a simple ratio times 100. It is the headline number of any synthesis — a measure of how efficient the reaction and your technique really were, and the figure every lab report and process chemist lives by.

Reviewed: June 19, 2026 · Author: Naveen P N, Founder — AI Calculator · Verified against: the definition of percentage yield.

The percent-yield equations

Percent yield
% yield = (actual yield / theoretical yield) × 100
Actual & theoretical
actual = theoretical × (% / 100) · theoretical = actual / (% / 100)
Loss to inefficiency
loss = theoretical − actual = theoretical × (1 − %/100)

Both yields must be measured in the same units — grams with grams, or moles with moles — because the ratio relies on like-for-like quantities; the units then cancel and leave a pure percentage. The theoretical yield comes from a stoichiometry calculation on the limiting reactant, while the actual yield is whatever you weigh out, dried and pure. The gap between them is the product lost along the way.

Worked example — a synthesis

Scenario: A reaction has a theoretical yield of 10 g, and you isolate 8.5 g of dry pure product.

Percent yield
% = (8.5 / 10) × 100 = 85%
Loss
loss = 10 − 8.5 = 1.5 g (15% lost)

An 85% yield is a good result — 1.5 g, or 15%, was lost to side reactions and handling. If you only recovered 5 g, the yield would drop to 50%, signalling something to improve in the method. And if you weighed 10.5 g, the apparent 105% yield would be a red flag that the product is still wet with solvent or contaminated, not that you broke conservation of mass.

Frequently Asked Questions

How do you calculate percent yield?

(actual ÷ theoretical) × 100. 8.5 g actual from a 10 g theoretical = 85%. Same units both sides.

Actual vs theoretical yield?

Theoretical = max from the balanced equation/limiting reactant; actual = what you really isolate. Actual ≤ theoretical.

Why is my yield below 100%?

Side reactions, incomplete reaction, losses in filtering/transfer, impure reagents. 70–90% is typically good.

Can yield be over 100%?

No — it signals wet/impure product or a wrong theoretical value. Dry fully and recheck the limiting reactant.

How do I find theoretical yield?

From the balanced equation: limiting reactant → moles → mole ratio → moles product → grams via molar mass.

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