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🧪 Acids & Bases

pH and pOH Calculator

Enter any one of pH, pOH, [H⁺] or [OH⁻] and get all four at 25 °C — plus whether the solution is acidic, neutral or basic.

pH ↔ pOH
[H⁺] & [OH⁻]
Acidic / basic
pH + pOH = 14
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pH & pOH — Quick answer

At 25 °C the two add to 14, and each is the negative log of an ion concentration.

pH + pOH = 14 · [H⁺] = 10⁻ᵖᴴ · [OH⁻] = 10⁻ᵖᴼᴴ

Worked example: pH 3 → pOH 11, [H⁺] = 10⁻³ M → acidic.

Examples

pHpOHType
311acidic
77neutral
8.55.5basic

The sum of 14 holds at 25 °C (Kw = 1×10⁻¹⁴).

🧪 pH and pOH Calculator

Pick what you know, enter the value.

pH
pOH
[H⁺] (mol/L)
[OH⁻] (mol/L)

ℹ️ At 25 °C: pH + pOH = 14, [H⁺] = 10⁻ᵖᴴ, [OH⁻] = 10⁻ᵖᴼᴴ. Concentrations must be positive.

pH and pOH measure acidity and basicity on a log scale. At 25 °C they satisfy pH + pOH = 14, with [H⁺] = 10⁻ᵖᴴ and [OH⁻] = 10⁻ᵖᴼᴴ. Enter any one of the four and this calculator returns the rest and tells you whether the solution is acidic, neutral or basic.

Reviewed: June 20, 2026 · Author: Naveen P N, Founder — AI Calculator · Verified against: Kw and the log definitions, recomputed in code.

The relationships

At 25 °C
pH = −log₁₀[H⁺] · pOH = −log₁₀[OH⁻] · pH + pOH = 14 · Kw = [H⁺][OH⁻] = 10⁻¹⁴

The "p" means "−log₁₀ of," so each unit of pH is a tenfold change in [H⁺]. Because water's ion product Kw is 10⁻¹⁴ at 25 °C, the two logs always sum to 14. Acidic solutions have more H⁺ than OH⁻ (pH < 7); basic solutions have more OH⁻ (pH > 7); pure water is neutral with both at 10⁻⁷ M.

Worked examples

pH 3:

acidic
pOH = 14 − 3 = 11 · [H⁺] = 10⁻³ M · [OH⁻] = 10⁻¹¹ M

[H⁺] = 0.01 M:

pH 2
pH = −log(0.01) = 2 · pOH = 12 · [OH⁻] = 10⁻¹² M

pOH 4:

pH 10 (basic)
pH = 14 − 4 = 10 · [OH⁻] = 10⁻⁴ M · [H⁺] = 10⁻¹⁰ M

A pH of 8.5 gives pOH 5.5, with [H⁺] ≈ 3.16×10⁻⁹ M and [OH⁻] ≈ 3.16×10⁻⁶ M — basic, since there's a thousand times more hydroxide than hydrogen ion.

Frequently Asked Questions

What is the relationship between pH and pOH?

At 25 °C, pH + pOH = 14, from Kw = [H⁺][OH⁻] = 10⁻¹⁴.

How do I convert pH to [H⁺]?

[H⁺] = 10^(−pH). pH 3 → 0.001 M. Reverse: pH = −log₁₀[H⁺].

How do I find pOH from [OH⁻]?

pOH = −log₁₀[OH⁻]. [OH⁻] = 10⁻⁴ → pOH 4, pH 10.

What pH is acidic or basic?

Below 7 acidic, 7 neutral, above 7 basic (at 25 °C).

Why is the sum 14 only at 25 °C?

Kw changes with temperature, so neutral pH and the sum shift away from 7 and 14.

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